Author Topic: outdoor noise reduction as distance increases  (Read 6887 times)

a.j

  • Guest
outdoor noise reduction as distance increases
« on: October 05, 2003, 11:53:18 PM »
How does a dB reading measure in theory as distance increases?



eg:



1m (meter) 90dB

2m = ?

4m = ?

8m = ?

64m = ?



is it frequency dependant as well?



I am thinking of lower frequencies, and  I thought I read on line  that it reduces spl by 6dB for every doubling of distance.



If so, that scenerio above would be:



start at 90dB at 1m

2m = 84dB

4m = 78dB

8m = 72dB

16m=66dB

32m=60dB

64m=54dB



and is it true that the threshold for lower bass is in this 50dB range?



lets get some replies...

aj

scott

  • Guest
Re: outdoor noise reduction as distance increasesS
« Reply #1 on: November 17, 2003, 01:41:13 AM »
Here's a calculator I found to help with the inverse square law.  Of course, this calculation works outdoors, not indoors.  
http://www.mcsquared.com/dbframe.htm

Stupid for replying

  • Guest
Re: outdoor noise reduction as distance increases
« Reply #2 on: February 28, 2004, 10:57:25 AM »
 :-X :-X :-X :-X :-X :-X :-X :-X :-X :-X :-X

The length of a lower frequency wave is about 16 ft.
The amplitude will noticeably increase at around 12.5 ft.
But after that, the volume will decrease, until about 25 ft from the source when it will increase some, but not as much as the first 16 ft....... and so on.

 

anything